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7z^2-343=0
a = 7; b = 0; c = -343;
Δ = b2-4ac
Δ = 02-4·7·(-343)
Δ = 9604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9604}=98$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-98}{2*7}=\frac{-98}{14} =-7 $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+98}{2*7}=\frac{98}{14} =7 $
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